2[-5(3x+4)+5(4x-4)]=

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Solution for 2[-5(3x+4)+5(4x-4)]= equation:


Simplifying
2[-5(3x + 4) + 5(4x + -4)] = 0

Reorder the terms:
2[-5(4 + 3x) + 5(4x + -4)] = 0
2[(4 * -5 + 3x * -5) + 5(4x + -4)] = 0
2[(-20 + -15x) + 5(4x + -4)] = 0

Reorder the terms:
2[-20 + -15x + 5(-4 + 4x)] = 0
2[-20 + -15x + (-4 * 5 + 4x * 5)] = 0
2[-20 + -15x + (-20 + 20x)] = 0

Reorder the terms:
2[-20 + -20 + -15x + 20x] = 0

Combine like terms: -20 + -20 = -40
2[-40 + -15x + 20x] = 0

Combine like terms: -15x + 20x = 5x
2[-40 + 5x] = 0
[-40 * 2 + 5x * 2] = 0
[-80 + 10x] = 0

Solving
-80 + 10x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '80' to each side of the equation.
-80 + 80 + 10x = 0 + 80

Combine like terms: -80 + 80 = 0
0 + 10x = 0 + 80
10x = 0 + 80

Combine like terms: 0 + 80 = 80
10x = 80

Divide each side by '10'.
x = 8

Simplifying
x = 8

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